使用互斥量同步
erhuabushuo
posted @ 2012年9月09日 16:03
in C
, 1319 阅读
#include <stdio.h> #include <unistd.h> #include <stdlib.h> #include <string.h> #include <pthread.h> #include <semaphore.h> void *thread_function(void *arg); pthread_mutex_t work_mutex; #define WORK_SIZE 1024 char work_area[WORK_SIZE]; int time_to_exit = 0; int main() { int res; pthread_t a_thread; void *thread_result; res = pthread_mutex_init(&work_mutex, NULL); if (res != 0) { perror("Mutex initialization failed"); exit(EXIT_FAILURE); } res = pthread_create(&a_thread, NULL, thread_function, NULL); if (res != 0) { perror("Thread creation failed"); exit(EXIT_FAILURE); } pthread_mutex_lock(&work_mutex); printf("Input some text. Enter 'end' to finish\n"); while (!time_to_exit) { fgets(work_area, WORK_SIZE, stdin); pthread_mutex_unlock(&work_mutex); while (1) { pthread_mutex_lock(&work_mutex); if (work_area[0] != '\0') { pthread_mutex_unlock(&work_mutex); sleep(1); } else { break; } } } pthread_mutex_unlock(&work_mutex); printf("\nWaiting for thread to finish...\n"); res = pthread_join(a_thread, &thread_result); if (res != 0) { perror("Thread join failed"); exit(EXIT_FAILURE); } printf("Thread joined\n"); pthread_mutex_unlock(&work_mutex); exit(EXIT_SUCCESS); } void *thread_function(void *arg) { sleep(1); pthread_mutex_lock(&work_mutex); while (strncmp("end", work_area, 3) != 0) { printf("You input %ld characters\n", strlen(work_area) - 1); work_area[0] = '\0'; pthread_mutex_unlock(&work_mutex); sleep(1); pthread_mutex_lock(&work_mutex); while (work_area[0] == '\0') { pthread_mutex_lock(&work_mutex); sleep(1); pthread_mutex_lock(&work_mutex); } } time_to_exit = 1; work_area[0] = '\0'; pthread_mutex_unlock(&work_mutex); pthread_exit(0); }
2012年9月10日 03:29
GLib 有一個基於 mutex 的更簡單的方法:
G_LOCK_DEFINE_STATIC (lock);
int lock = 1;
void do (void)
{
G_LOCK (lock);
lock ++;
G_UNLOCK (lock);
}
2012年9月10日 15:06
@Mike: 好的 寻寻资料学习下
2024年1月15日 22:04
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